Could everyone help me calculate the gold content of this gold mine?
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This post was last edited by jinghua21 on 2010-7-19 at 16:11. I have an oxidized gold mine here, covering an area of about 150 mu; the oxidized ore is present beneath the layer of mud on the surface. The thickness of this mud layer ranges from one to two meters, and once that mud is removed, the red-colored oxidized ore becomes visible. The thickness of the oxidized ore layer is more than two meters, and beneath it lies the virgin ore. The depth of the virgin ore has not yet been determined. Next to this mine, there is an inclined shaft dug by someone else earlier, with a depth of around 200 meters. The results of the tests conducted on the samples of the oxidized ore taken separately showed a weight of over 3 grams, while the cyanidation recovery test indicated a recovery rate of around 78%-83%! Could everyone help calculate the reserve of this mine?
The total gold reserve in the oxide ore seams is approximately 1.3–2.0 tons.
There’s so much of it! ! I’m afraid I’ve miscalculated! Hehe
The method for calculating the specific gravity of oxidized ore isn’t specified, but it can be determined by carrying out a specific gravity test. If the specific gravity is 3.5 T/m3, then the total gold reserve in the oxidized ore layer is more than 2 tons.
This is what I calculated; why is it so different from what you have? 25 acres = 151.757 mu, and 151.757 mu = 101,171.41056 square meters. Assuming a thickness of over 2 meters for the oxidized ore layer, with 2 meters taken as the value, the volume is 202,342 cubic meters. If the content per ton, as determined by testing, is over 3 grams, then the total storage amount is 607,026 grams
Reply to 5# jinghua21: Are you referring to 3 grams per ton or 3 grams per cubic unit? If it’s 3 grams per ton, you need to multiply the volume by the weight per cubic unit and then multiply that result by 3 grams. If it’s 3 grams per cubic unit, then your calculation is correct.
The test result is 3 grams per ton, not per cubic meter
Well, you still ask about such a simple calculation.
How much is this mine worth? It doesn’t seem like much, does it?