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I want to design an ammonia dissolution heat utilization device. If anyone has experience, let’s discuss it together! Our current heat source is a mixed gas of ammonia and water under 1.6MPA conditions, with ammonia content accounting for 50%. How to make good use of this dissolved heat is the main problem now? Those with experience can discuss it together.
Why is no one replying? Is it because they don’t understand or something? Let me tell you in detail: I have a flash gas with a pressure of 1.5MPA (temperature of 155 degrees). It is mainly water and ammonia, each accounting for 50% by mass. Isn’t the heat of dissolution of ammonia very large? Now I want to add water and convert the heat of dissolution into latent heat. Is it possible to use it? Please give me some advice. Thank you.
Thermodynamics can work on the market, but it’s hard to say whether it can be done on your equipment.
The host learns first* Let’s start with materialization or heat transfer. In addition, search for the establishment of the second law of thermodynamics, which started from studying the efficiency of steam engines. Research shows: The heat engine efficiency η (the fraction of heat absorbed by the high-temperature heat source that is converted into work) of any heat engine (a machine that converts heat into work, such as a steam engine) working between two heat sources of high temperature T1 and low temperature T2, has the highest efficiency ηr of a heat engine (i.e., a reversible heat engine) whose working process is a reversible process (see thermodynamic process), and ηr = (T1-T2)/T1. The working process of this reversible heat engine is called the Carnot cycle. This law is called Carnot's theorem, which is the basis for efficient use of energy. Thermal engine efficiency is related to the temperature difference between high and low temperatures of the working fluid. The gasoline engine is above 400 degrees, and the diesel engine is even higher. The efficiency is about 30%. The efficiency limit of your machine is about 10 to 20%. Including actual heat loss, mechanical loss, etc., it does not exceed 10%.
Reply 4# Your host’s equipment seems to have nothing to do with what you are talking about!