Thread Content
There is currently an alkali solution with a concentration of 30%. It needs to be diluted to a 10% concentration in a container. The container already contains a 10% concentration of alkali solution; how much water needs to be added to reach that concentration?
Calculating it using formulas yields theoretical results, which differ significantly from the actual concentration obtained. There was originally 10% liquid level of weak alkali in the container; the height must be specified. It is recommended to use a hydrometer for measurement. Take samples while flushing and stirring, and once the density approaches the desired level, contact the laboratory for sample analysis
No volume was given, nor the concentration of the original alkali solution – how is this supposed to be calculated?
This post was last edited by mpcchuang on 2010-9-4 at 16:39. There is also the geometric progression method commonly used by workers; for example, if the tank is 5 meters high and contains a dilute alkali solution with a concentration of 10% over a depth of 1 meter at the bottom, and one has 30% concentrated alkali solution, then to prepare a 10% concentrated dilute alkali solution in the tank, it is necessary to take 1 meter worth of 30% concentrated alkali solution and add water up to a total height of 4 meters. Afterwards, the density is measured using a hydrometer and converted into a concentration value. Generally, the concentration of the alkali solution varies from top to bottom in the tank; especially when only 1 meter remains, the concentration will no longer be 10%. Therefore, it is necessary to use a hydrometer when the water level is approaching 2 meters. This geometric progression method is not suitable for horizontal containers
The original poster hasn’t even listed all the conditions; even if a solution is given, will he be able to understand it?
Calculate using the cross method. 30 – 10 = 20; 0 – 10 = 10. 10:20 = 1:2, which means 1 part of alkali and 2 parts of water. If a 100% concentration is desired, then: 100 – 10 = 90; 90 / 3 = 30. In other words, add alkali until the concentration reaches 40%, and then add water until the concentration reaches 100%. Is that correct? Please advise