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Heat exchanger design, newcomer seeking help

2010-09-27View Original

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These days, my supervisor gave me a problem requiring the calculation of the heat exchange area; steam flows in the tube side, with an inlet temperature of 130°C and a pressure of 0.2 MPa. Water flows in the shell side; the inlet temperature is 40°C and the outlet temperature is 80°C, with a pressure of 0.2 MPa. The flow rate is 200 kg/h, and the diameter of the heat exchange tubes is 19 mm. What is the heat exchange area? How can it be calculated? I calculated that the flow rate in the shell side is around 0.05 KJ/KG, while that for steam is only 0.004 KJ/KG, right? Is it smaller? . . I’m asking my older brothers and sisters to help answer this
Reply #22010-09-27
The heat exchange area is required; the unknown parameters in your conditions are the mass flow rate of steam and the outlet temperature. Therefore, you need to solve a set of equations, and the specific equations can be found in the section on convective heat transfer in the principles of chemical engineering.
Reply #32010-09-27
Reply to 2# yj851225: But this is heat transfer with phase change, a condenser, right? I can’t find it
Reply #42010-09-28
Why isn’t anyone helping me? Ughhh
Reply #52010-09-28
First, take a look at the section on heat transfer in \"Principles of Chemical Engineering\" and understand the heat transfer film coefficients in cases with and without phase changes; once that’s clear, things will be easier.
Reply #62010-09-28
This can definitely be handled using a plate exchanger. I’ll do the calculations for you – 2 m2 will be sufficient. The original poster also said that, according to my calculations, the flow rate in the shell side is around 0.05 KJ/KG, while that for steam is only 0.004 KJ/KG, right? Is it smaller? . . Why is the flow rate in KJ/Kg? ?
Reply #72010-09-28
Add me on QQ. I’ll use software to calculate it for you. . 25971934
Reply #82010-09-28
Q=KA(T1-T2)=CPM(T1-T2)=KW=3600KJ/H
Reply #92010-09-28
Please provide a detailed explanation of the poster’s calculations. I also want to know how to calculate the heat exchange area.
Reply #102010-09-28
Reply to 6# dqpihejing: I’m sorry, I typed it wrong; it should be kg/s
Reply #112010-09-28
Reply to 5# cgp188: It’s very difficult to calculate, and there are several quantities in those formulas that I can’t find information on

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