Hood efficiency
Thread Content
How can the pressure drop from the outlet of the main fan to the inlet of the flue gas extractor be reduced, in order to improve the recovery efficiency of the flue gas extractor and maximize its functionality?
1. Increase the main air flow to improve the recovery efficiency of the flue gas extractor. 2. Reduce the opening degree of the double-acting slide valve, so that as much flue gas as possible flows through the flue gas extractor. 3. In accordance with the design pressure difference requirements for the regenerator and the reactor, the regeneration pressure can be increased appropriately, provided that normal production is not affected.
Increasing the main air volume and appropriately raising the regeneration pressure can improve the recovery efficiency of the flue gas turbine, but it also increases the power consumption of the main fan. Minimize the opening degree of the double-acting slide valve, keep the high-temperature butterfly valve fully open, and ensure that as much flue gas as possible flows through the flue gas extractor – this is the key to improving the recovery efficiency of the flue gas extractor
What was said on the third floor is correct; we do it the same way in our devices, and the results are good. Of course, it is also possible to consider improvements in the efficiency of the exhaust fan itself; our company is currently working on technical upgrades.
1. Use a one-way damping valve with low pressure drop at the outlet of the main fan, as well as gate valves and butterfly valves at the inlet of the exhaust fan (with a pressure drop of less than 10 KPa; ideally, 5 KPa)； 2. Control the low level in the regenerator (value permitted by process control) ； 3. The primary air valve and secondary air valve of the auxiliary combustion chamber are fully open.
Reply to 5# aqshhsq: May I ask? This low reserve? What does that mean? Won’t a low reserve level affect the circulation rate and activity of the catalyst?
W=△P*S → △P=W/S. Here, W represents the storage volume, △P represents the pressure drop, and S represents the cross-sectional area of the bed layer. When the cross-sectional area of the bed layer remains constant, the pressure drop is proportional to the storage volume; therefore, the pressure drop decreases as the storage volume decreases.
To improve the efficiency of smoke exhaust systems, it is related to the selection of the equipment itself, the design of the smoke ducts and blades, as well as regular maintenance. As for increasing the energy recovery efficiency of such systems, it essentially involves minimizing losses throughout the entire process; what was said above is quite professional.