The relationship between the pump’s power and shaft power
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What is the relationship between the pump’s power and its shaft power, and what is its relationship with the motor’s power? I need to know it urgently! Thank you!
The last edit to this post was made by 0237967500 on 2010-10-29 at 15:57. The ratio of effective power (which is the pump’s head multiplied by the density of the fluid, multiplied by g, and multiplied by the flow rate of the fluid) to shaft power is the pump’s efficiency. The power of the motor, that is, the power of the pump’s electric motor, is equal to the shaft power
Motors or other prime movers and equipment are connected using couplings; the power of the prime mover multiplied by the efficiency of the coupling gives the shaft power, and shaft power multiplied by the efficiency of the pump gives the power of the pump. That’s how it should be, right?
1. When P-axis ≤ 15KW: (Motor power) = 1.25 × (P-axis). 2. When 55KW ≥ P-axis ≥ 15KW: (Motor power) = 1.15 × (P-axis). 3. When (P-axis) ≥ 55KW: (Motor power) = 1.1 × (P-axis). In our pump industry, this is the standard method used to calculate motor power. Note: The calculated (P-motor) value is used to select the motor model from the reference motor samples. And the calculation of shaft power: Pshaft = (density × 9.8 × flow rate × head) / (1000 × pump efficiency)