I have a few questions regarding the flow rate of ethylene compressors
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While studying *ethylene compressors, we encountered this question: \"The flow rate in the first stage of an ethylene compressor is equal to the flow rate at the top of the suction tank in that stage; the flow rate in the second stage is the sum of the flow rates in stages one and two; the flow rate in the third stage is the sum of the flow rates in stages one, two, and three.\" Dear friends, how should we understand this question? Thank you all!
The ethylene compressor uses multi-stage compression: the flow rate at the top of the inlet tank in the first stage is compressed, then it proceeds to the second stage of compression and subsequently to the third stage. Therefore, the flow rate entering the second stage consists not only of the flow rate from the top of the inlet tank in the second stage but also of the flow rate that comes after compression in the first stage. As a result, the flow rate in the second stage equals the sum of the flow rates from the tops of the inlet tanks in the first and second stages. Similarly, section 3 is equivalent to the sum of the flow rates at the tops of the suction tanks in sections 1, 2, and 3. Of course, in general, there is no need for a flow transmitter at the top of the three-stage suction tank, as it is sufficient to measure the flow at the outlet of the third stage (in the case of three-stage compression). It’s quite simple once you understand it; keep it up!
What was said on the second floor is correct; the ethylene compressor system is a closed-loop system, and yours features three stages of compression. There are three inlets and one outlet; therefore, the flow rate in a certain section is the sum of the flow rates from the preceding sections plus the inflow to that section.
Thank you to all my friends for sharing their valuable advice; thanks!