Calculation of the fluid resistance in the shell side of the water cooler
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The heat exchanger is of the fixed-tube-sheet type; the shell side carries a gas containing 25% steam at a temperature of 135 degrees Celsius, while the tube side carries condensed water. When calculating the fluid resistance in the shell side, the shell side pressure drop is determined using the Esso method: ΣΔP0 = (ΔP′1 + ΔP′2) * FsNs, where ΔP′1 represents the pressure drop as the fluid passes through the tube bundle, and ΔP′2 represents the pressure drop when the fluid passes through the baffle plates. The fluid resistance can be calculated in two parts; non-condensable gases can be calculated using the formula above. But how should the fluid resistance of the condensed water vapor be calculated? During the condensation process, temperature and pressure decrease; how should the pressure drop across the fluid flowing in the shell side be calculated? Thank you for your guidance
I didn’t expect that there would still be people who calculate the pressure drop manually. 1) Are your tubes bare tubes? Are there no fins or extended areas to enhance heat transfer? 2) How is the flow area for condensation divided up? Is there any desuperheating or subcooling involved? 3) The calculation model I saw is: Total pressure = Pressure drop in the inlet nozzle + Pressure drop in the inlet baffle area + Pressure drop in the central baffle area + Pressure drop in the outlet baffle area + Pressure drop in the outlet nozzle + Pressure drop due to static head. Don’t ask me for the specific formulas; I’m not a theoretical researcher. 4) Is this heat exchanger horizontal or vertical? I hope to provide you with some useful feedback. Good luck!
Reply to 2# bestleemh: Working in a factory involves many aspects of design, and manual calculations are required; I’m also frustrated as the results of those calculations don’t seem to be correct
Use it with ASPEN (including HTFS heat exchanger design calculations).