How is the evaporation rate of a cooling tower determined?
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The flow rate of the cooling tower in my company is 100 tons per hour. I would like to know what the water loss is; please have an expert analyze it for me!
This is related to the local temperature conditions. Please refer to the book \"Industrial Water Treatment\" written by Mr. Shuho Honma, which contains the calculation formulas.
Reply to 1# Mountains: Qe=K△TQ, where k is the calculation coefficient, △T is the temperature difference between the inlet and outlet of the cooling tower, and Q is the volume of water circulating in the system. The value of K is given by: Temperature (°C) – 100: 0.0008; 100: 0.0010; 200: 0.0012; 300: 0.0014; 400: 0.0015; 500: 0.0016
Reply to 3# aoxue: Could you make the K value more visible? It’s not clear enough.
The design specifications for circulating cooling water are very detailed. The losses of water include losses due to discharge (related to the concentration ratio), losses caused by wind, and evaporation losses; the specific percentages can be found in the specifications
Just calculate using the latter method; it’s more accurate. This is the formula I use myself. E = Q * (-0.00000013 * POWER(T,2) + 0.00002 * T + 0.001013) * (t2 – t1), where Q is the amount of water circulating in the system, E is the amount of evaporation, T is the average ambient temperature, t2 is the water temperature at the top of the tower, and t1 is the water temperature at the bottom of the tower; all temperatures are measured in degrees Celsius. With a computer, just enter the equal sign along with the parameters behind it, and that’s the answer.