Evaporation of ammonia
Thread Content
I would like to ask the experienced colleagues: how many cubic meters of gaseous ammonia can 1 cubic meter of liquid ammonia evaporate into at normal pressure? Thank you!
It should be possible to do it through thermodynamic calculations! For the PVT relationship, how about using the RK equation? Hehe
It depends on the temperature of the liquid ammonia, as its density is related to temperature. The density of liquid ammonia can be determined from the temperature, after which the number of moles of liquid ammonia can be calculated. Using the state equation, the volume of gaseous ammonia at standard pressure can then be determined
The density of liquid ammonia is approximately 600 kg/m3; thus, one cubic meter contains about 600 kg of ammonia. With an atomic weight of 17 for ammonia, the number of moles is 35.294 kmol. Using the ideal gas law at standard pressure, the volume of gaseous ammonia is 39.294 * 22.4 = 790.5 m3.
It can be calculated using PV=(m/M)RT.
Approximately 1 ton of liquid ammonia can evaporate to yield 1316 Nm3 of gaseous ammonia, which can be calculated based on the specific gravity at the corresponding temperature.