A gauge question?
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When a throttling device was designed, the density of the fluid was 520 Kg/m3; however, in actual use, the density of the fluid is 480 Kg/m3. If, during design, the differential pressure transmitter produced a output of 100 Kpa corresponding to a flow rate of 50 t/h, what would be the corresponding flow rate in actual use?
There are formulas available in chemical engineering principles; the original poster should go back and check the books.
This can’t be calculated; it’s better to take a look at the equipment to understand it clearly!
Use the differential pressure flow formula; it’s in the textbook on chemical engineering principles.
It’s probably around 52T; you can verify this using the formula, as there is a relationship between flow rate, density, and pressure difference.
Recalculate the differential pressure element and the differential pressure. Factors such as medium density, viscosity, range, temperature, and pressure are all important factors that affect differential pressure measurement. It’s generally difficult to find accurate answers to such questions on the internet, as such calculations require relevant parameters and software.
If the differential pressure remains unchanged, the calculated value is 48 T/H
This post was last edited by *aobodao on 2011-1-15 08:27. If all other parameters remain constant, the mass flow rate is proportional to the differential pressure and the square root of density； The volumetric flow rate is proportional to the square root of the pressure difference, and inversely proportional to the square root of the density ； At all actual densities, Q=50*【480/520】1/2=48; red indicates the square root.
The calculation should be done in proportion to the square root of the flow rate and differential pressure. The result should be roughly 52 t/h.
Q design/Q actual == √(ρ actual/ρ design) The correct answer is 52 T/H