Can flame-retardant shielded control cables be used for powering 220VAC?
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This post was last edited by sdqust on 2011-3-22 at 16:16. In other words, can ZR-KVVRP be used in ZR-VVR applications? Also, could an expert help calculate this: for a device with a power rating of 0.5 KVA and a distance of 300 meters, will 2x1.5 mm2 power cables be sufficient?
. . I think there shouldn’t be any problem; it’s just an extra shielding layer. As long as the cable is thick enough, it should be fine
Sure. Generally, we keep the diameter of the cables used at 1–1.5, while power cables require a diameter of 2.5–6. The choice of cable diameter depends mainly on factors such as the transmission distance of the power signal, the power of the power supply device, as well as the minimum voltage and current required for power supply
Sure, the electric stoves and microwaves left over from previous construction projects have worked fine. PS: Check the wire diameter and calculate the load.
Is there no expert who can solve it? ? 、
A 2*1.5 cable can be used as a power cord, but for the situation you described, I do not recommend using this type of cable; a thicker one should be used instead.
It’s possible. Generally, the voltage tolerance level of control cables is 500V; as long as the cross-sectional area is sufficient, there will be no problems. The shielding layer can also be used as a ground wire, making it equivalent to a 3-core cable, which provides greater safety
Assuming it is a purely resistive circuit, with the electrical device having a rated voltage of 220V and a rated power of 500W, then the impedance of the device is RL = U²/P = 96.8Ω, and the current is I = 2.27A. Vmin represents the lowest supply voltage allowed for the device to operate. According to GB/T 12325—2003, the allowable deviation for a 220V single-phase supply voltage is +7% and –10% of the nominal system voltage. The lowest voltage in the supply system is 220x(1–10%) = 198V; thus, Vmin = 198 – 2.27XR, where R represents the resistance of the wiring. The resistance coefficient of copper at t = 75°C is ρ = 0.0217Ω·mm²/m. In this way, L=R/((ρX1.5X2)) can be used to make the calculation; this is based on a calculation method for determining the cable length of pressure transmitters that can be found in a forum
Is there any expert in electrical engineering who can do the calculations?
Is there any expert in electrical engineering who can do the calculations? Urgently needed online
As long as the cable’s voltage tolerance is sufficient, there will be no problem