One Question per Day on Chemical Equipment 2011.04.07
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A certain device selects a centrifugal oil pump for transporting crude oil at a temperature of 225°C. The pump’s flow rate is Q = 572 cubic meters per hour, its head is H = 237 meters of water column, its efficiency is 70%, and the density of the oil is 0.80 tons per cubic meter. What is the shaft power required for this pump? Solution: N = QHγ/367η = 572×237×0.8/367×0.70 = 422 (kilowatts)
Reply 1# zhouhuihubei P=HQρg/(3600η)=237*572*9.81*800/(3600*0.7)=422185W=422kW
This post was last edited by yanghoudaodaye on 2011-4-7 02:09. Shaft power N = QHr/102e; Q – flow rate； H – Head ； r-liquid density ； e – Pump efficiency = 1519
Shaft power = Flow rate × Head × 9.81 × Specific gravity of the medium ÷ 3600 ÷ Pump efficiency = 572×237×0.800÷(0.7×3600) = 43.04 kw
Reply 1# zhouhuihubei 486.3KW
N = QHγ/367η = 572×237×0.8/367×0.70 = 422 (kilowatts)
158803000kg.m/h