Calculation of metering pump power?
Thread Content
1. How to calculate the power of a metering pump? How to choose the motor power? 2. The shaft power P = Q*H/(102*η), where H is the head; when the inlet and outlet pressures of the pump are known, how is this converted into head? (For example, if the outlet pressure of a metering pump is 40 Mpa and the medium is a chemical agent, what is the corresponding head in meters?) ）
Why isn’t anyone answering? . . . .
Dear poster, you yourself understand the formula very well; so I ask you, how can you determine the range without Q (flow rate)? That is, you have an electric heater; you only know that the temperature in your room is 5 degrees Celsius, but you haven’t told us how big the room is. How can we then determine the appropriate power rating for it?
Regarding the original poster’s question (for example, if the outlet pressure of the metering pump is 40 Mpa and the medium is a chemical agent, what is the corresponding head in meters?) To calculate the head required, one needs to know the density. We know that density * g * h = p; assuming the density of the medium is the same as that of water and g is taken as 10, then 1000 * 10 * h = 40 * 1000000, which gives a head of 4000 meters. Personally, I think this value is too high; the original poster should check whether it should be 40 Mpa instead
40MPa is highly unlikely! Centrifugal pumps are generally not designed this way
Passing by Xue*, haha – as the person above said, the question is problematic.
An outlet pressure as high as 40 MPa
When choosing a plunger pump, we do not consider the head; we are only concerned with the flow rate.