Preparation of dilute sulfuric acid
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I want to prepare 50% dilute sulfuric acid with a water flow rate of 1 ton per hour. How much 93% concentrated sulfuric acid is needed? It would be great if you could provide me with a calculation formula.
Based on the law of conservation of mass, assuming that the mass flow rate of 93% sulfuric acid is X/H, we have: 93%X = 50%(X + 1). The calculation result is: X = 2.33
Reply 3# qugd, isn’t that correct? How much is that? ? ?
This answer can’t be correct; water flows at 1 T per hour, so shouldn’t concentrated acid require 2.33 T?
The formula on the second floor is correct; it’s just the calculation of the result that’s wrong. It should be x=1.16
When 98% sulfuric acid is added drop by drop to water at room temperature to prepare dilute sulfuric acid, a large amount of heat is released. May I ask the teachers, what cooling device is the most economical and effective to use? Our company’s current manufacturing process is relatively outdated; it uses jacket cooling, with a heat exchange area of only 10 square meters. Frozen water at -5 degrees Celsius is required for cooling in order to meet the production needs.
A graphite-sulfuric acid dilution cooler can be used; this device first mixes concentrated sulfuric acid with water to dilute it, and then cools it down to the desired temperature. For details, contact via QQ: 1928192414.