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file:///C:/DOCUME~1/ADMINI~1/LOCALS~1/Temp/ksohtml/wps_clip_image-14884.png I would like to ask the experts here: regarding the electricity bill shown above, do \"current reading\" and \"previous reading\" refer to the amount of electricity used? I also have another question – how can one calculate the average electrical power? There is also the concept of magnification; please include the formula when calculating
I can’t see the picture you sent; please send it again using another method.
Reply to 2# czywqa: If you take a closer look, you can still see it clearly. I’ve dealt with this several times as well, and this is the clearest version yet.
I can’t see the image. Please send it again
Reply to 2# czywqa: Electricity bill for March 2011 – Utility name: **; Reading this period, reading last period, multiplier, electricity consumption (KW.h), loss (10%), unit price (yuan/KW.h), amount (yuan). Meter reading date: 15531341801696016960; Value: 0.8811643620; Date: 2011-3-25. To calculate the average power: I’ve prepared a new table; it should be clearer this time. The key is how to calculate the average power.
Reply to 4# stone822: Electricity bill for March 2011 – Utility name: **; Reading this period, reading last period, multiplier, electricity consumption (KW.h), loss (10%), unit price (yuan/KW.h), amount (yuan). Meter reading date: 15531341801696016960; 0.8811643620; 2011-3-25. To find the average power: It’s this meter – it should be clear now. The key is to find the average electrical power.
Electricity cost = (Current period – Previous period) × 80 × 1.1 × 0.88 = (1553 – 1341) × 80 × 1.1 × 0.88 ≈ 16,436 yuan
Reply to 7# czywqa: Could you explain the meaning of this formula? And how is the average electrical power calculated?
This issue — this month’s electricity meter reading; Previous period — Electricity meter reading from last month ; 80 — Power supply voltage (0.4 KV) × current transformer turns ratio (1000/5); 1.1 — Electricity consumption for this month plus losses ; 0.881 —— price per unit of electricity. Average electrical power – The average instantaneous power consumption this month is (for example: Total electricity used this month / 30 days / 24 hours = (16860 + 1686) / 30 / 24 ≈ 26 KW)
Reply to 9# czywqa: Thank you, I finally understand what’s going on.