Knowing the heat absorption of moist air, how can one determine the required amount of water?
Thread Content
Given the moisture content d (g/kg) of moist air, and the heat absorbed by the moist air q (in kJ/kg), I want to use the latent heat of vaporization of water, which is 2501 (in kJ/kg). How can I determine the amount of water I need to add using these known conditions? The teacher said to use q/2501, but that way the units are canceled out. I can’t figure it out for now; please advise me. My email: 154331983@163.com
One can be smart their whole life, but make a mistake at some point. The heat absorbed Q (in KJ) is known, and the latent heat of vaporization of water is 2501 (unit: kJ/kg). Find the amount of water in KG. Therefore, Q/2501 = (KG); the result is in kg
Reply to 3# 154331983: It’s obviously a mistake in the question, right?
The unit of q cannot be kJ/kg
The calculation result is in kg of water per kg of dry air; how can such units be canceled out, haha.