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How to calculate the heat occupied by the deaerator?

2011-05-23View Original

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Part of the heat coming out of the waste heat boiler is sent to the deaerator; how is this amount of heat calculated?
Reply #22011-05-23
It generally accounts for 3% of the rated evaporation rate.
Reply #32011-05-23
This post was last edited by dongjiang1001 on 2011-11-9 at 18:40. Heat Q = steam volume x steam enthalpy (the enthalpy corresponding to the temperature and pressure of deaerated steam).
Reply #42011-05-23
This post was last edited by dongjiang1001 on 2011-11-9 at 18:40. What 729 said is pretty much correct, but not entirely accurate. It should be: Heat Q = amount of steam x (enthalpy of steam – enthalpy of steam when it becomes saturated water). The heat required is equal to the enthalpy difference resulting from heating deoxygenated water to a saturated state; a small margin (for heat loss) is sufficient.
Reply #52011-05-25
This post was last edited by dongjiang1001 on 2011-11-9 at 18:41. Generally, according to empirical formulas, to heat water to the saturated temperature of 104 degrees at the deaerator, the amount of steam required is 15% of the boiler’s rated steam output; that is, for a boiler with a rated evaporation capacity of 10 tons, the steam input to the deaerator should be 1.5 tons. The same principle applies in similar cases.
Reply #62011-11-09
If what the comrade on the 5th floor said is correct, then this will be very practical.
Reply #72011-11-29
I think what was said on the 5th floor is a bit vague; the amount of steam required has to be calculated. Personal opinion: Assuming that the heat source steam required for deoxygenation is a t/h, and the enthalpy difference between this heat source steam and the saturated water it becomes is h, then the energy provided by the heat source is: a*h. The water replenishment amounts are as follows: steam turned into saturated water at a rate of a t/h, condensate at a rate of c t/h (with the temperature of the condensate being t1), and fresh feedwater at a rate of d t/h (with the temperature of the fresh feedwater being t2). The total amount of water used in the deaerator is therefore e = a + c + d t/h. The temperature of the mixture of condensate and fresh feedwater is t3: t3 = (c*t1 + d*t2) / (c + d). The enthalpy value of water at this temperature is h1; the enthalpy value of saturated water at the outlet of the deaerator is h2. Thus, the amount of steam required to heat the feedwater is: h*a = (c + d)*(h2 – h1). The value of a represents the steam consumption, while the heat quantity required is given by Q = (c + d)*(h2 – h1)

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