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I hope everyone can help me analyze the float interface gauge

2011-06-01View Original

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Our company has several float-type level gauges, which are used to measure two different types of fluids: alkaline solution (density 1.03) and solvent oil (density 0.68). The process is currently in hydro-link mode; one range is 140 CM of liquid level. The magnetic flap indicates zero only when the level is at 90 CM, meaning that a liquid level between 90 and 140 CM corresponds to 0% to 100% for the float. I don’t understand how to test the interface at that time; please help me analyze it. Thank you for this~~
Reply #22011-06-01
I haven’t worked with floats for many years… Back then, they were pneumatic. In short, there are two methods available to you: the first is to calculate the difference in buoyancy, that is, the range, and then adjust the float accordingly; subsequently, it can be moved to the new location on-site (if the required distance for movement is sufficient). The second method involves using weights – by calculating the weights needed for the zero point and the range, the float can be calibrated directly. This is the standard method.
Reply #32011-06-01
100%... means that the entire buoy is submerged in the alkali solution; the weight required is equal to the buoy’s weight minus the buoyancy it experiences when completely submerged in the alkali solution. 0%... means that 50 CM of the buoy is above the solvent oil, with the remaining length of the buoy submerged in the alkali solution. The sum of the buoyancies from these two sections constitutes the total buoyancy of the buoy at 0%, and by subtracting this total buoyancy from the buoy’s weight, we obtain the weight required at 0%. I’m just speaking as I think... if there are any mistakes, please feel free to point them out
Reply #42011-06-02
The indications in the water intermodal transport are fine. Float interface meter, used to measure two types of media: alkali solution (density 1.03) and mineral oil (density 0.68). When the medium is entirely solvent oil, it indicates 0% ; When all are alkali solutions, it indicates 100%. When 140CM is completely filled with solvent oil (density 0.68), the buoyant force acting on the float is almost the same as that when it is 90CM deep in water. No problem.
Reply #52011-06-02
Reply to 3# blue--sky: I made a mistake; I forgot to consider the water intermodal transport status... My zero-point calculation is incorrect. Please don’t pay attention to this, hehe
Reply #62011-06-02
I didn’t calculate it carefully... The theory regarding the 4th floor is correct; my reply on the 3rd floor was wrong. I’m sorry
Reply #72011-06-03
Reply to 4# wangyongan: I still don’t understand. How can I see the liquid levels of two different media when it’s in normal operation? ? ? ? ?
Reply #82011-06-04
Reply to 7# wangsong123: First, you need to have an understanding of the interface for measuring the float. Buoyancy is generally related only to two variables: the length of the cylindrical float and the density of the medium... Based on what you’ve described, it can be estimated that the length of the float is around 140 CM (it’s likely that your flap level gauge was ordered with this value in mind as its operating height). A 0% output means that the float is completely submerged in solvent oil (with a density of 0.68); therefore, the height h at which the float needs to be submerged in water during operation can be calculated as follows: 140 (length of the float) × 0.68 (density of solvent oil) = h × 1.0 (density of water). The result is h = 95.2 CM. A 100% output means that the float is completely submerged in alkali solution (with a density of 1.03); thus, the height h required for the float to be submerged in water during operation is calculated as 140 (length of the float) × 1.03 (density of alkali solution) = h × 1.0 (density of water), giving a result of h = 144.2 CM. As you can see, 144.2 – 95.2 = 49 CM, which is roughly consistent with the range of 90–140 CM you mentioned for the height difference when using water. It’s important to note that since the density of alkali solution is greater than that of water, the actual output cannot reach 100% when the float is completely submerged in water; it will only be close to 100%. This is also why h = 144.2 CM is greater than the length of the float, which is 140 CM. Another point to consider is that the float and the flap may not necessarily be at the same level, even though their lengths might be equal. (Perhaps the float is 5 CM lower than the flap... hehe) In short, during normal operation, you won’t be able to see the liquid surface or the interface directly; everything is calculated. As long as your parameters are correct, that’s all for now... I’m so tired. I hope you can understand what I’ve said, hehe
Reply #92011-06-04
It’s more or less accurate. For float-type level gauges, as long as the densities of the liquid on the upper and lower layers are different, the indication is not meaningful. Hydro-transport, including during startup, requires the buoy to function properly only once the densities of the liquid being pumped in and out match those specified in the design. Buoyants work based on density; it’s simple to calculate them using density and length – for example, 1X0.9 is roughly equal to 0.6X1.4, so it’s more or less accurate.

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