For a 380V/40V transformer, if the power is cut at the input side, will the voltage at the output side disappear immediately?
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There is a 380V/40V transformer; if the contactor at the input side is disconnected, will the 40V voltage at the output side disappear simultaneously, causing the load connected to the 40V side to stop operating immediately?
The electrical circuit causes the resistive load to stop working immediately due to the loss of power supply. Capacitive and inductive loads also cease to function within milliseconds. And if the load is a rotating motor, due to the mechanical inertia of the motor, it will likely take several seconds for it to stop operating.
Agree with the opinion above. But if 40V is output after rectification (that is, 40V DC), the 40V voltage persists temporarily due to the presence of the electrolytic capacitor.
No, there will be a process of discharge light, as the transformer is an inductive load. Both inductive and capacitive loads are energy storage devices, so they need to release electrical energy.
I have an idea: if an auxiliary normally open contact from the incoming terminal contactor is connected in series with the coil of the outgoing terminal contactor (if it has one), wouldn’t that basically achieve simultaneous operation? I hope my colleagues can give me their feedback!
The student on the 6th floor has a good idea. But I think it would be safer to connect another resistor in series.
Is the current too high when the output terminal contactor is closed? Is that not good? Because the current at the low-voltage side is high.
Both inductive loads and capacitive loads have a discharge process. It is best to use a contactor to control the output, or add a freewheeling diode at the output.
The idea for the 6th floor is good, but we need to consider the size of the terminal contactors