Low-temperature methanol washing; seeking help for financial support
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I would like to ask everyone: if the ammonia concentration in low-temperature methanol washing is 20 Mg/L, what is the equivalent value in PPM?
1. If it is a mass ratio, then 1 ml of methanol weighs approximately 800 g; therefore, 20 mg/800 g = 25 ppm. 2. If it is on a molar basis, then 1 ml of methanol contains 25 moles, and 20 mg of ammonia contains 0.001176 moles; therefore, the concentration is approximately 47 ppm.
What was said upstairs is incorrect; 1 mL of methanol contains approximately 800 mg, and the molar mass of methanol is 32 mol/kg
The unit for molar mass was written incorrectly: 32g/mol
1 ml of methanol contains 800 mg; therefore, 1 L contains 800 g. Dividing 20 mg by 800 g gives 25×10^-6, which is 25 ppm.