I need help figuring out how much thermal energy (in KJ) is required to evaporate 1 Kg of water at 20°C
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This post was last edited by dongjiang1001 on 2011-8-24 17:52. Assuming no other factors need to be considered, I would like to know how much thermal energy (in KJ) is required to evaporate 1 Kg of water at 20°C?
This post was last edited by dongjiang1001 on 2011-8-24 at 17:52; the value of 594.5304 kcal/kg is actually the heat of vaporization.
This post was last edited by dongjiang1001 on 2011-8-25 08:20; it refers to the enthalpy difference between the initial state and the final state.
In addition to the latent heat of vaporization, there should also be the heat required to raise the temperature at constant pressure from 1 atm and 20°C in the liquid state to 1 atm and 100°C in the liquid state.
2590.937789KJ/Kg