Help with a question from reaction engineering
Thread Content
For a known n-th order irreversible chemical reaction A-B, under the same reaction temperature conditions, if the initial concentration of A is doubled, the reaction rate at the same conversion rate becomes twice the original value; then the order of this reaction is ( )
Reply 1# yu*njian011792: Doubling the initial concentration of A results in a reaction rate that is twice as high when the same conversion rate is achieved. This shows that when the initial concentration is doubled, the reaction rate also doubles at the same conversion rate, indicating that the space time remains unchanged. According to the space time formula, only the first-order formula at constant temperature is independent of the initial concentration; it depends on the conversion rate and the reaction equilibrium constant. Therefore, the reaction order should be 1. I’m not sure if it’s correct?
This post was last edited by hector-csl on 2011-9-5 09:08 with r=kCa,0(1-X). Doubling the initial concentration doubles the rate. Level 1 is correct.