How to calculate the calorific value of the volatiles generated during the calcination of pre-baked anode petroleum coke
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Gentlemen, I have just joined HaiChuan. I admire the skills of all of you, and I would be grateful if you could do me a favor. How is the calorific value of the volatiles generated during the calcination of petroleum coke calculated?
Volume of flue gas generated per hour: Serial number, Flue gas volume Vn, Number of tanks, Discharge capacity, Actual yield, Volatile matter content, Amount of volatile matter, Unit for flue gas generated: 1: 3360, 8, 90, 0.75, 0.1, 1.4, 25 m3; 2: 5040, 12, 90, 0.75, 0.1, 1.4, 25 m3; 3: 10080, 24, 90, 0.75, 0.1, 1.4, 25 m3; 4: 12600, 30, 90, 0.75, 0.1, 1.4, 25 m3; 5: 26880, 48, 120, 0.75, 0.1, 1.4, 25 m3. Heat generated per hour (per production line): Serial number, Heat quantity Q, Flue gas volume, Inlet temperature, Specific heat capacity, Outlet temperature, Specific heat capacity, Coefficient, Unit: 1: 604884, 3360, 900, 0.367, 400, 0.352, 0.95 Kcal/h; 2: 907326, 5040, 900, 0.367, 400, 0.352, 0.95 Kcal/h; 3: 1814652, 10080, 900, 0.367, 400, 0.352, 0.95 Kcal/h; 4: 2268315, 12600, 900, 0.367, 400, 0.352, 0.95 Kcal/h; 5: 4839072, 26880, 900, 0.367, 400, 0.352, 0.95 Kcal/h
Note: Delayed petroleum coke (10%–12% of the petroleum coke itself) generates flue gas at temperatures of 850°C–980°C, with a flue gas volume of 3000–9000 Nm3/t·unit. Calculation example: Assuming 8 calcination tanks, with 90 kg of material discharged per tank per hour (when the air excess factor is 3.0), the flue gas volume is Vn = 8×90÷0.75×0.10×1.4 m3×25 = 3360 m3/h. Here, 8 refers to the 8 tanks; 90 represents 90 kg per tank per hour; 0.75 is the actual yield percentage; 0.10 is the volatile matter content percentage. When the air excess factor is 3.0, 25 m3 of flue gas is generated per cubic meter of volatile matter, and 1.4 m3 of flue gas per kilogram of volatile matter.