Theoretical calculation
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I would like to ask the experts: What is the equivalent volume in standard cubic meters for 2.5 kilograms of air at room temperature, which occupies 108 m³? How is it calculated? And how is it calculated for other gases? Kneel in gratitude! ! ! ! ! ! ! ! !
Could someone give me some advice? ! ! ! ! ! ! ! ! ! ! ! !
This post was last edited by rockmantom on 2011-12-5 at 15:54. Using the ideal gas equation, V_standard = T_standard/T_actual * P_actual/P_standard * V_actual
I'm sorry. I study mechanics, but I don’t quite understand it. Could you please give me an example? Thanks! ! ! ! ! ! ! !
This post was last edited by rockmantom on 2011-12-6 08:27. The standard condition is 0°C and 100 KPa (1 kilogram). The unit for T is K; T_standard = 0°C + 273.15 K, and T_actual = room temperature + 273.15. P_actual = 2.5, P_standard = 1. V_actual = 108 m3
Could you please calculate it for me? ! ! The temperature is 40 degrees Celsius
I calculated it to be 14,130 Nm³. So what about liquefied gas? How to calculate it? Thanks first! ! ! ! ! ! ! ! !
Which ones can be treated as ideal gases, and which ones cannot?
I hope an expert can give an answer. Thank you! ! ! ! ! ! ! ! ! ! ! ! 1
V standard = 273.15/(273.15+40)*1/2.5*108 = 37.68
No matter what gas it is, just change to the corresponding parameters; if converting to standard volume, it is equivalent to assuming an ideal gas