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Technical assistance: How to calculate the amount of sulfuric acid required for water pretreatment? ?

2011-12-07View Original

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This post was last edited by hesonchang214 on 2011-12-11 at 11:25. The pH of the water is 7.6; it is desired to adjust the pH to 6.0–6.5 while keeping the water volume at 1,000 cubic meters. Treatment with 98% concentrated sulfuric acid is to be used – how much sulfuric acid should be added? ? Everyone, please help take a look!
Reply #22011-12-08
The pH of the make-up water is 7.6; it is desired to adjust the pH to 6.0–6.5, with a water volume of 1,000 cubic meters. Treatment will be carried out using 98% concentrated sulfuric acid – how much sulfuric acid should be added? ? First, calculate the alkalinity at a pH value of 6.0, determine its molar amount, and then, based on the amount of water you have available, figure out how many moles of sulfuric acid are needed. That’s fine.
Reply #32011-12-08
Reply to 2# Ordinary Life: The boss didn’t provide the alkalinity value for 6.5, so he asked us to calculate it. We don’t know how to do that – could you please explain it in detail? ? Thank you!
Reply #42011-12-08
Tests need to be conducted; the pH value and acidity are not in a one-to-one correspondence.
Reply #52011-12-09
The last edit to this post was made by Ordinary life on 2011-12-9 at 13:51. There is a theoretical formula for calculating pH and alkalinity, which applies in three different scenarios; water from various locations uses different calculation methods, though these are only approximate values. At a pH of 6.5, it is 11.5 milligrams per liter (moderately hard to moderately alkaline as well as low-alkaline soft water, with a hardness of 50–300 and a base saturation of 50–300) ; 25. 7 (moderately alkaline soft water, hardness 50–150, alkalinity 200–300) ; Ultra-soft water has a value of 5.5; this is just an approximate figure and not necessarily accurate – experiments are needed to determine the exact value.
Reply #62011-12-09
This is for internal use; it’s best to perform a titration with distilled water and that will suffice
Reply #72011-12-19
This is simple: subtract the alkalinity required for water balance from the alkalinity that needs to be controlled, then divide by 1000 to get the number of kilograms to add per ton of water.

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