Pump head issue
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Hello everyone, I have a question. Flow rate: 30 cubic meters per hour; medium: ammonia water. After the pump outlet, the flow splits into two branches that connect to the inlets of two towers, with the height of these inlets being 40 meters. The pressure at the inlet and outlet is approximately equal. I would like to ask: when calculating the pump head, should I use 40 plus the resistance loss of the two pipes, or 80 plus the resistance loss of the two pipes? It feels like the former, but I don’t know why; Bernoulli’s equation doesn’t provide an explanation
Personally, www.whwlbf.com thinks it’s the former
For the former, it is obtained by listing the Bernoulli equation·····
It is recommended to revise fluid mechanics pumps and fans
If the two pipes are of the same height and have the same material as well as the same friction coefficient, then the outlet resistance will be identical; the head pressure will be 40 meters plus half of the flow rate times the resistance of one pipe, plus a safety factor
What was said on the 5th floor is correct; that’s how it’s calculated
It should be 40 in height, but the liquid head needs to take into account the weight of the liquid in both pipes.
The algorithm on the 5th floor is correct; neither of the two methods mentioned by the original poster is right