Sulfuric Acid Section – Daily Question for December 14
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This post was last edited by “I Love Chemical Engineering” on December 14, 2011, at 14:33. When SO2 and O2 are mixed in a volume ratio of 1:3, they are introduced into a contact chamber where the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g) takes place. At equilibrium, under the same temperature and pressure, the ratio of the densities of the mixture before and after the reaction is found to be 71:80. What is the conversion rate of SO2? The answer to the previous question on the 13th: The reaction of adding quicklime to sulfur-containing coal to \"fix sulfur\" is CaO + SO2 → CaSO3, and 2CaSO3 + O2 → 2CaSO4. It can be seen that the types of reactions involved are combination reactions, redox reactions, non-redox reactions, and non-ionic reactions.
Reply to 1# I love chemical engineering 90%, sofa?
Reply to 1# I love chemical engineering 40%
The calculated conversion rate should be 90%, and the density ratio is actually the reciprocal of the volume ratio
Based on the fact that, under the same conditions, the ratio of the densities of gases is equal to the ratio of their masses in the same volume, and that mass is conserved before and after a reaction, it can be concluded that the ratio of the densities of gases is inversely proportional to the volume of the gases. Let the volume of SO2 in the mixed gas before the reaction be 1 L, and that of O2 be 3 L. The volume of SO2 that is converted at equilibrium is x. 2SO2(g) + O2(g) ≒ 2SO3(g)
Total volume, V/L (initial): 1, 3, 0, 4 L
Volume, V/L (after conversion): 2x, x, 2x
Volume, V/L (at equilibrium): 1–2x, 3–x, 2x, 4–x
Since the ratio of the densities of gases is equal to the inverse ratio of their volumes, we have:
71 : 80 = (4 – x) : 4
x = 0.45 L. Therefore, the amount of sulfur dioxide that has converted is 0.9 L. The conversion rate of sulfur dioxide is:
0.9 L ÷ 1 L × 100% = 90%
Total volume, V/L (initial): 1, 3, 0, 4 L
Volume, V/L (after conversion): 2x, x, 2x
Volume, V/L (at equilibrium): 1–2x, 3–x, 2x, 4–x
Since the ratio of the densities of gases is equal to the inverse ratio of their volumes, we have:
71 : 80 = (4 – x) : 4
x = 0.45 L. Therefore, the amount of sulfur dioxide that has converted is 0.9 L. The conversion rate of sulfur dioxide is:
0.9 L ÷ 1 L × 100% = 90%
Reply to 1# I love chemical engineering: 0.9L÷1L×100%=90%
The sulfur dioxide conversion rate is 90%