How to calculate the cross-sectional area of a φ133X6 fitting
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How to calculate the cross-sectional area of a φ133X6 fitting
Isn’t it just the surface area for circulation? The area of the inner circle
This should be pretty simple, right? What does the moderator mean by that question? Can’t believe it
Isn’t it just the area of a circle: L. . . . . .
This post was last edited by Feitianxue on 2012-1-17 at 14:49. It seems to me that what he is referring to is the cross-sectional area of the inlet and outlet areas as well as the total cross-sectional area of the heat exchange tubes; it’s likely that this is the area he needs. I’m not sure if I’m correct! My personal understanding!
133 is the outer diameter; the inner diameter is 133–6*2=121. The area is then calculated as Π(121/2)^2. . It’s obvious they’re a newbie just like me. . What is needed are answers, not methods. . .
Questions must be precise and clear. Otherwise, it’s difficult to answer. A question like yours should be understood as referring to the cross-sectional area of the metal, that is, the area of the ring.
The cross-sectional area of the pipe section being taken over is the area of the ring; whereas the cross-sectional area for flow is the area of the inner circle
The question is too simple; I don’t even dare to give an answer! !
What is the technical level of it? :lol
The cross-sectional area of the pipe section being taken over is the area of the ring; whereas the cross-sectional area for flow is the area of the inner circle