May I ask, what is the heat transfer coefficient for cooling a powder using water? Thank you
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May I ask, what is the heat transfer coefficient for cooling a powder using water? Thank you
It cannot be specified without operating conditions; a reference value of 0～∞ is given.
:Lol, Hmm.. Water: 30-35; toner: 420-50. Toner output: 340 kg/h. The heat amount I calculated is: 145802200 J/h
:( Some kind of network error??? An error message appeared; it turns out that the data was uploaded, but the popularity values were all negative.) . . . . Dizzy
Do you design such cooling equipment for others? What type is it?
No, it was my own sudden ideaaaaaaaaahhh
Hehe, is that so? So, what’s the progress now? Any advancements?
:Lol, I saw the diffusion theory, and then... . . . . . . . . . . . . . . I can’t bear to watch any longer.
The carbon powder mentioned by the original poster is a non-Newtonian fluid, and conventional calculation formulas cannot yield the desired results.
I don’t know what kind of toner it is; is it amorphous toner? Graphite powder? Diamond powder? They are both carbon, but their heat transfer coefficients differ by a huge margin. I think you should avoid water cooling; using an air cooling system will definitely give good results.
What was said upstairs makes sense – it’s carbon black, which has a low heat transfer coefficient, but one that is still higher than that of air. In terms of ranges, if it is stirred up, could its heat transfer coefficient become higher than that of air-water?