Reciprocating compressor flow rate calculation
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A gas has a temperature of 40°C, a flow rate of 6000 Nm³/h, and a pressure of 0.7 Mpa (gauge pressure). After being compressed by a compressor, its temperature rises to 80°C and its pressure increases to 1.2 Mpa (gauge pressure). What is the flow rate of the gas at this point? The answer is 4164 Nm·h. Please provide the calculation process, thank you.
PV/T = constant; note that temperature is in absolute terms and pressure is in absolute terms as well. The Nm you wrote might be problematic.
Could you do the specific calculation? I can’t do it myself.
P1V1/T1=P2V2/T2
6000*0.8/（273.15+40）*（273.15+80）/1.3
I studied it; it’s been many years since I last used textbooks
Isn’t absolute pressure equal to gauge pressure plus one atmosphere? Or I must have remembered it wrong\ud83d\ude04
In my knowledge, atmospheric pressure is always considered to be 1 bar, unless precise calculations are required, in which case it’s different