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Why does the flash tank of a sulfur plant have two drain ports with the same nominal diameter?

2018-07-21View Original

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This post was last edited by Deadandgon_XPWA on 2018-7-21 at 14:55. Why does the flash tank in a sulfur processing unit have two drain ports with the same nominal diameter?
Reply #22018-07-21
This post was last edited by ylb913 on 2018-7-21 at 16:33: Flash tank for rich amine solution? There is a baffle at one end, which is used for skimming oil; the two waste discharge ports are located on either side of the baffle. In this diagram, only one drain port (oil drain port) can be seen; the other drain port is located on the pipeline at the amine liquid outlet.
Reply #32018-07-21
Does that mean the liquid discharged from one end of the partition contains oil, while it does not contain oil at the other end?
Reply #42018-07-21
This post was last edited by ylb913 on 2018-7-21 at 20:41. As shown in the diagram, the main part of the flash tank is the space to the left of the partition, while the space on the right of the partition used for oil skimming serves as an auxiliary function of the flash tank. The inlet and outlet of the amine solution are both on the left side of the partition. Normal liquid level control is around 50%, with upper and lower limits at 30% and 70%, while the height of this partition is at 83% of the liquid level. ——The idea behind this design is to artificially raise the liquid level in the flash tank for a short period of time when draining oil. ——To be honest, this design at this height isn’t necessarily reasonable; I use the term “the tip of the iceberg” to describe the concept of oil skimming. Assuming the specific gravity of the oil is 0.67 and a 50% liquid level is maintained as standard, the height of the oil above and below this 50% level is in a 1:2 ratio; when the left side is entirely filled with oil, the actual liquid level is only 75% (not reaching 83%). The assumed density of 0.67 for this oil is already low enough. For example, if the specific gravity of the oil is 0.8, then the actual liquid level when the container on the left is full is 50%/0.8 = 62.5% (1:4), which is even further away from 83%.

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