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Question: Questions 31 and 35 in the morning session of the first day of the 2014 Chemical Engineering professional examination

2015-06-02View Original

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31. What is the value of the degree of freedom for the gas-liquid equilibrium system of a binary material solution? (A)2 (B)3 (C)4 (D)1 35. At 20°C, the vapor pressures of methanol and ethanol are 12.5 KPa and 5.9 KPa respectively. These two substances can be considered to obey Raoult’s law over a wide range of compositions. Therefore, what is the vapor pressure (in KPa) of a mixture composed of 50 kg of methanol and 100 kg of ethanol at 20°C? (A)10.30 (B)9.74 (C)8.66 (D)8.10
Reply #22015-06-03
This post was last edited by ydm4585 on 2015-6-3 10:34. At constant temperature and pressure: 2-2+2=2. First, calculate the molar fractions of each component in the mixture; then the result is obtained by multiplying X1 by 12.5 and X2 by 5.9. No further detailed calculation is needed. Constant temperature and constant pressure; the last number is 2, which is incorrect
Reply #32015-06-03
For question 31, the degree of freedom is 2, right? Determining two states in tpxy is enough to fix everything
Reply #42015-06-03
What is the value of the degree of freedom for the gas-liquid equilibrium system of a binary material solution? (A) At 20°C, the vapor pressures of methanol and ethanol are 12.5 KPa and 5.9 KPa respectively. These two substances can be considered to obey Raoult’s law over a wide range of composition values. Therefore, what is the vapor pressure (in KPa) of a mixture composed of 50 kg of methanol and 100 kg of ethanol at 20°C? (C)8.66
Reply #52015-06-03
8.10 Choose D 12.5*0.3333+5.9*0.6666
Reply #62015-06-03
Ugh, what’s needed is the molar fraction, not the mass fraction. That’s how it should be understood; factors such as concentration are influenced by the number of molecules, that is, by moles, rather than by their weight, that is, mass.
Reply #72015-06-03
Haha, yes, it’s my fault. I was looking too quickly; I’m starving. Sorry about that
Reply #82015-06-03
Choose C, 8.66, determined based on the molar ratio! :P
Reply #92015-07-08
Oh, after reading the post, I realized that’s where my problem lay :)
Reply #102016-08-23
I have a question: where does this 2-2+2 come from?

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