HCBBS Forum (English)

Can a 37KW self-priming pump achieve a flow rate of 180 m3/h and a head of 40 M?

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Purple sweet potato
Reply #22016-11-30
What medium is it, and what’s its density?
Reply #32016-11-30
It still depends on the density value, ρgHQ – calculate it
Reply #42016-11-30
This post was last edited by sifangok on 2016-11-30 at 11:24. If the company’s pump selection table contains a suitable model, then there will be no problem
Reply #52016-11-30
Pumping water is generally possible; it won’t work if the medium is too heavy.
Reply #62016-11-30
If the motor coefficient is taken as 1.15, the water pump efficiency must be at least 64% to meet the requirements……
Reply #72016-12-01
The effective power of the pump (in KW) = flow rate × density × head × 9.81/3600. The power required for selecting the motor = effective power of the pump / efficiency / transmission efficiency × motor safety factor; generally, when selecting a motor, it is sufficient to use the coefficient of effective power divided by 0.4 to 0.45. In this case): 180X40X9.81/3600/0.45=43.6KW; a 37KW motor is basically not sufficient for this purpose, so it is recommended to use a motor with a higher capacity. You can find the pump selection parameter table from the manufacturer and compare it.
Reply #82016-12-01
Our company uses a water pump with a flow rate of 210 m3/h, a head of 40 m, and a motor power of 37 KW; this is for reference only.
Reply #92016-12-01
Can a 37KW self-priming pump achieve a flow rate of 180 m3/h and a head of 40 M? The shaft power of the pump was discussed at length above; to meet the required conditions, it is necessary to take into account factors such as temperature, density, viscosity, self-priming height (whether it is a negative or positive elevation), and the pressure drop in the inlet pipeline in order to determine whether the specified conditions are satisfied.

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