【毎日一問】理論基礎 2019.7.11
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選択問題：CaCO3(s)、CaO(s)、BaCO3(s)、BaO(s)、CO2(s)からなる平衡系の自由度は： (A)F=2 (B)F=1 (C)F=0 (D)F=3 答え：C。物質は合計5種類、化学反応は2つあるため、C=5-2=3となり、相の数は5つで、F=C-P+2=0となる。 ヒント：答えの返信は表示されます
固相と気相の二相ではないのか、なぜ相数は5になるのか？
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