工芸基礎知識（選択問題）20181016

2018-10-16View Original

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同じ凝縮温度において、R12、R134a、R22を冷媒とした場合の凝縮圧力の大きさの順序は次の通りである。 A．PR22>PR12>PR134A B．PR134A>PR22>PR12 C．PR22>PR134A>PR12 D．PR134A>PR22>PR12

Reply #22018-10-16

C．PR22>PR134A>PR12

Reply #32018-10-16

Aを選んでください。でも、この問題のBとDにはどんな違いがあるのですか？

Reply #42018-10-16

A．PR22>PR12>PR134A B

Reply #52018-10-16

A．PR22>PR12>PR134A

Reply #62018-10-16

B．PR134A>PR22>PR12　D．PR134A>PR22>PR12　同じ

Reply #72018-10-16

C．PR22>PR134A>PR12

Reply #82018-10-16

この投稿は最後に、飛鴻踏雪666によって2018年10月17日10時03分に編集されました。同じ凝縮温度のもとで、R12、R134a、R22を冷媒とした場合の凝縮圧力の大きさの順序はR22＞R134a＞R12です。間違えていたらCを選ぶべきでした

Reply #92018-10-16

2213412~~~~~~~~Cを選ぶ

Reply #102018-10-16

C．PR22>PR134A>PR12

Reply #112018-10-16

C．PR22>PR134A>PR12

Reply #122018-10-16

C．PR22>PR134A>PR12

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工芸基礎知識（選択問題）20181016

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