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一式を求める

2018-11-15View Original

Thread Content

電流と差圧の比率の計算式はどうやって求めるのか
Reply #22018-11-15
(400-100)/(500-100)=(x-4)/(20-4),よってx=16mA
Reply #32018-11-15
(測定値-測定範囲下限)/(測定範囲上限-測定範囲下限)=(電流値-4mA)/(20mA-4mA)
Reply #42018-11-15
学んだことを実践に活かし、一つを知って他を類推する。中学校の先生が教えてくれた二項式方程式の解き方:lol
Reply #52018-11-15
…測定範囲の下限は4mAに対応し、上限は20mAに対応するので、わかりますよね

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