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2017-03-24View Original

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Reply #22017-03-24
R2R’N +H2S—→ R2R’NH++HS—(快速反应) 由于MDEA的N原子上没有孤对电子,因此MDEA不能直接与CO2反应,只有在水溶液下才能发生如下反应: R2R’N+CO2+H2O—→ R2R’NH++HCO3—(慢速反应) R2R’N+CO2—→不反应 显然:MDEA与H2S、CO2的反应,存在着反应速度的差异,而MEA、DIPA与H2S 、CO2的反应却无此差异,因此MDEA在有CO2存在的条件下对H2S 有较好的选择吸收能力。 慢反应不等于不反应,因为反应慢,所以优先吸收硫化氢,在塔盘数满足吸收硫化氢合格的情况下,再增加塔盘,吸收完硫化氢的MDEA会在多余的塔盘上进一步吸收二氧化碳,从而导致最终所看到的选择性降低。
Reply #32017-03-30
变差说的是MDEA选择性吸收,二氧化碳和硫化氢与MDEA反应分别是慢反应和快反应,塔板增加相当于增加反应时间,时间一长,二氧化碳吸收自然增强,选择性下降。
Reply #42017-03-31
相对来说,MDEA更容易吸收H2S,但并不代笔不吸收CO2,当H2S吸收已经接近饱和的情况下,增加塔板数,会进一步吸收CO2,造成选择性下降。

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