化学工学基礎 - 物理化学
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単原子理想気体 2 mol の場合、断熱過程の△ (pv) = -26KJ より、その過程の体積仕事 W = A26KJ B-39KJ C-65KJ D39KJ 答え：-39KJをどう理解するか
断熱過程、Q=0、△U=W=nCv、m(T2-T1)=1.5nR(T2-T2)=1.5(P2V2-P1V1)=1.5△(PV)=-39Kj
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