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差圧流量計の平方根問題について。

2016-06-30View Original

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疑問があります。圧力差変換器のQ/Qmax=√ΔP/√ΔPmax=√I/√Imaxという式は正しいのでしょうか?また、平方根を取る際は、パーセンテージに対して取るのか、圧力差に対して取るのか、それとも4-20mAに対して取るのか? 大神にご教示をお願いします。
Reply #22016-06-30
圧力差と圧力差の測定範囲の比率 X 流量の測定範囲=流量 ÷ パーセンテージの平方根

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