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2020-07-23View Original

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Reply #22020-07-23

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Reply #32020-07-23

Reply #42020-07-23

A、HAc解离度增大；

Reply #52020-07-23

A、正确解析： A．稀释醋酸时，促进醋酸电离。故A正确； B．稀释醋酸时，促进醋酸电离，醋酸根离子、氢离子的物质的量增大，醋酸分子的物质的量减小，但醋酸根离子、氢离子的物质的量增大程度小于溶液体积增大程度，所以醋酸根离子、氢离子、醋酸分子浓度都减小，但氢氧根离子浓度增大，故B错误； C．醋酸的电离平衡常数只与温度有关，温度不变，醋酸的电离平衡常数不变，故C错误； D．加水稀释醋酸，促进醋酸电离，氢离子的物质的量增大，醋酸分子的物质的量减小，故D错误；故选A．

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