【每日一题】理论基础2020.08.04

2020-08-04View Original

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本帖最后由青涩年华于 2020-8-4 08:20 编辑选择题：Kθs（Mg（OH）2）=5.6×10-12，则Mg（OH）2在0.01 moldm-3 NaOH溶液中的溶解度为（） A、5.6×10-9moldm-3 ， B、5.6×10-10moldm-3 ，C、5.6×10-8moldm-3 ， D、5.6×10-5moldm-3 答案：C 提示：能阐述出解题过程的给予额外奖励，答案回复可见

Reply #22020-08-04

C。5.6x10(-12)/(0.01x0.01)=5.6x10(-8)

Reply #32020-08-04

C： ^2=5.6×10^-12 ×0.01^2=5.6×10^-12 =5.6×10^-12/10^-4=5.6×10^-8 氢氧化镁在在0.01mol.L-1NaOH溶液中的溶解度是5.6×10^-8mol/L.

Reply #42020-08-08

C、5.6×10-8moldm-3

Reply #52020-08-12

C、5.6×10-8moldm-3

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【每日一题】理论基础2020.08.04

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