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[" [{"每日一题"}], [{"이상일"}, {"이론적기초"}, {"2...............D"}], [{"객-choice"}, {"....D], [{"3.3D.D}D-"}, {"D], [{"D], [{"B.-烷烃D命名原则는:D找出最长的碳碳链当D主链D,依D碳数D命名D主链DD前十个以以天D甲、乙、丙...D代表D数数数D数数D数数数D数D数数D当D主链D,从最近的D取代基位置编号:D、、D33(使使得D取代基的位置数字越小越D好D数字与与中文D数字D之间D以以以隔D;有有有有有有D有有D有有DD有D有DDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD], {"所以A不对D当D应该是D-D甲D戊D烷D;DCDCD,;C不对D当D应该是D-D乙DD33333;D;D;D;DD],D所以D所以答案DDBD]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D]D pérdida de tiempo.]

2020-09-17View Original

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选择题:按系统命名法,下列有机化合物命名正确的是( ) A. 2—乙基丁烷; B. 2,2—二甲基丁烷; C. 3,3—二甲基丁烷; D. 2,3,3—三甲基丁烷 答案:B 提示:能阐述出解题过程的给予额外奖励,答案回复可见
Reply #22020-09-17
B. 2,2—二甲基丁烷;
Reply #32020-09-17
B. 2,2—二甲基丁烷;
Reply #42020-09-17
B 烷烃的命名原则是:找出最长的碳链当主链,依碳数命名主链,前十个以天干(甲、乙、丙...)代表碳数,碳数多于十个时,以中文数字命名,如:十一烷;从最近的取代基位置编号:1、2、3...(使取代基的位置数字越小越好)。以数字代表取代基的位置。数字与中文数字之间以- 隔开;有多个取代基时,以取代基数字最小且最长的碳链当主链,并依甲基、乙基、丙基的顺序列出所有取代基;有两个以上的取代基相同时,在取代基前面加入中文数字:一、二、三...,如:二甲基,其位置以 , 隔开,一起列于取代基前面。A不正确,应该是3-甲基戊烷;C不正确,应该是2,2 —二甲基丁烷;D不正确,应该是2,2,3一三甲基丁烷,所以答案选B。

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