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["[". 每일 일 문제 泵设备】간단问答

2019-03-08View Original

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N. 본 토스 마지막 N 3
Reply #22019-03-08
能吧,毕竟有一个大气压的过盈压力,换算下来相当于好多米位差。管路阻力没提,一般也不会太大。要是入口配的管径过细,倒是有可能阻力过大,造成泵汽蚀。
Reply #32019-03-08
可以。不考虑阻力的条件下,泵入口压力(G)+大气压-介质此温度下的汽化压力(A)=有效气蚀余量 大约10m水柱>3.4m+0.5M
Reply #42019-03-08
可以正常使用,装置汽蚀余量NPSHA=入口压力(相对)+大气压力(绝)-汽化压力(绝)>泵汽蚀余量NPSHR+0.6(安全余量),0.94+0.1-0.94=0.1(约10米水柱),10>3.4+0.6=4
Reply #52019-03-08
可以,0.1+0.94-0.034-0.94>0
Reply #62019-03-08
可以正常使用,经计算泵入口绝压为1.04MPa,大于汽化压力。
Reply #72019-03-08
可以正常使用,装置汽蚀余量NPSHA=入口压力(相对)+大气压力(绝)-汽化压力(绝)>泵汽蚀余量NPSHR+0.6(安全余量),0.94+0.1-0.94=0.1(约10米水柱),10>3.4+0.6=4
Reply #82019-03-08
可以正常使用,装置汽蚀余量NPSHA=入口压力(相对)+大气压力(绝)-汽化压力(绝)>泵汽蚀余量NPSHR+0.6(安全余量),0.94+0.1-0.94=0.1(约10米水柱),10>3.4+0.6=4
Reply #92019-03-08
可以正常使用,装置汽蚀余量NPSHA=入口压力(相对)+大气压力(绝)-汽化压力(绝)>泵汽蚀余量NPSHR+0.6(安全余量),0.94+0.1-0.94=0.1(约10米水柱),10>3.4+0.6=4
Reply #102019-03-08
可以正常使用, 装置汽蚀余量NPSHA=入口压力(相对)+大气压力(绝)-汽化压力(绝)>泵汽蚀余量NPSHR+0.6(安全余量),0.94+0.1-0.94=0.1(约10米水柱),10>3.4+0.6=4
Reply #112019-03-08
能 ((1.04-0.94)/1)x102=10.2m>3.4+1.1m,不发生汽蚀

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