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2019-04-13View Original

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Reply #22019-04-13
"기프트 초전류의 원인입니다.",
Reply #32019-04-13
"본 게시물은 David3kkkkk 님이 2 년 4 월 1 일 1:0 에 마지막으로 편집했습니다. 한 기프트,,额定流量是1 m3/h이며, 매체 밀도는 약 0.85-0.87g/cm3이며. 실제 운송량은 약 1吨/h이며. 자주 초전류가 발생합니다. 어떤 이유가 있을까요?",
Reply #42019-04-13
"이렇게 표현하면 원인을 분석할 수 있을까요? 만약 해당 펌프가 원래 매체 밀도가 약 0.5로운다면? 펌프의 매개변数发发一下吧,扬程是113m,进口压力是0.3MPa,出口压力是1.1MPa,操作温度是11摄氏度,电机额定功率是5kW,转速是515rpm,额定电流是61.1A
Reply #52019-04-13
"진동이 초과합니까? 진동이 초과되면 전류가 초과됩니다",
Reply #62019-04-13
"양정은 1m,进口压力是3公斤,出口压力是1.1公斤操作温度是1摄氏度电机额定功率是5kk瓦转速是55rpm额定电流是61.1A
Reply #72019-04-13
"额定流量是5方,密封是8那么就是是6吨/时扬程是1米进口3公斤就是是4米压力你现在出口是8公斤正常不超电流的。如果此时超电流三个数据需要审核一是流量是否准备二是压力是否准确三是泵是哪家生产的什么型号及效率多少你这个可能与泵有关。
Reply #82019-04-13
"비중是85进出压差没有问题
Reply #92019-04-13
"如果没有机械性的摩擦,那就指向了泵的效率口环间隙是不是太大导致回流量太大导致泵的效率下降。
Reply #102019-04-13
"泵的选型很重要。如果你的参数在该泵的工况点内已经是低扬程大流量了且已经是低效率的了此时你泵出口本应是8公斤压力又偏到了1公斤就属于严重偏工况了。泵效率下降电机超电流很正常。如果我表达的不清楚可以私聊一下。
Reply #112019-04-13
"p= 密度×g×H=85*187*113=6.84MPa加上进口压力3不就是6.8左右吗
Reply #122019-04-13
"水泵扬程是靠离心力甩出来的与密度也有关系?这个超出了我的知识范畴。
Reply #132019-04-13
"天啊这是初中物理加上高中物理学的压力跟密度没有关系?
Reply #142019-04-13
"按照你的的说法一米高的水柱跟一米高的水银产生的压力一样了
Reply #152019-04-13
"亲先把基础知识学一下吧
Reply #162019-04-14
"扬程是扬程压力是压力二者不是一个东西
Reply #172019-04-14
"对的我想起来了!扬程一样压力不一样。谢谢😊
Reply #182019-04-15
"扔石头与扔棉花效果能一样吗
Reply #192019-04-16
"与设计参数核实一下进行换算。

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