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2014년 전문고시 첫날 지식의 오후, 35문항

2016-07-25View Original

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섭씨 20도에서 메탄올과 에탄올의 증기압은 각각 12.5kPa와 5.9kPa입니다. 라울의 법칙에 따르면 섭씨 20도에서 50kg의 메탄올과 100kg의 에탄올로 구성된 혼합물의 증기압은 얼마입니까?
Reply #22016-07-25
포화 증기압을 곱하여 혼합 용액에서 메탄올과 에탄올의 몰분율을 계산합니다.
Reply #32016-07-26
대답은:x(메탄올, 몰%)=50/32/(50/32+100/46)=0.418, 따라서 x(에탄올, 몰%)=0.582입니다. 20도에서의 혼합액체의 증기압은 P=0.418x12.5+0.582x5.9=8.66KPa이다.

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