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["Sobre a HG 2268,-2268关于HG 2268中的烟囱自生通风压计算公式的问题"

2019-09-11View Original

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"A fórmula para o vento de autoventilação do chamina na HG 228168第37页给出烟囱自生通风风的公式为δP=8*h*(ρ空-ρ烟) *g/, fórmrmula para o vento de autoventilação do chufena na HG 68 é δP=8*h*(ρ空-ρ烟)*g/,注释里面ρ空和ρ烟分别为标准状态下空气和烟气的密度,这个公式与其他参考书上的公式不一样。从设计的角度应该参考规范,但是分析了一下,感觉参考书上的的公式更好理解。请高手和专家指导一下这个公式怎么理解。第一:通常计算中标准状态下空气和烟气的密度分别为1.33和1.34。如果把这两个数带入进去就为负数了,肯定是不正确的。第二:通常自生通风风(抽力)的计算是对空气密度和烟气密度做温度修正,在在高海拔地区还要做压力修正 这个公式也没有做修正感觉不太对啊;第三:外面的的系数一个8一个没有明确的的含义不知道什么意思。如果有宁波工程公司或者其他公司的专家,请帮忙答疑解惑一下谢谢。"
Reply #22019-09-11
"Este tó帖最后由 snakegqw 于 2 2-1 22:54 编辑 规范是告诉你用ρ空=1.336.3334进行实际进行实际温度校正计算密度。当烟气温度高高时其密度小于空气注意:校正后的单位仍然是kg/NM3不要误认为是°C下的标准大气压"

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