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Как решить эту задачу? ? ?

2019-02-26View Original

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16. Уравнение линии работы секции ректификации в ректификационной колонне имеет вид y=0,75x+0,216. Следовательно, коэффициент обратного потока составляет (B). А) 0,75 Б) 3 В) 0,216 Г) 1,5
Reply #22019-02-26
R/(R+1)=0,75, следовательно, R=3

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