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The pressure drop across the secondary pipe dropped instantly from 6 kPa to 4 kPa, and the solid content of the slurry increased to 35%; it is suspected that the single suspension valve cannot be closed. How should the pressure balance for the single suspension be calculated? How is 6 kPa calculated?
There’s a problem with the single suspension; it seems that it can’t be closed properly. The voltage drop associated with the single suspension refers to the voltage drop at the inlet and outlet. I don’t understand how this figure is calculated Where did the pressure loss go?
How was it calculated? How to tell if it’s too big or too small, and whether the material leg is blocked or can’t be closed? Where does the pressure drop go?
How to calculate it? What is its relationship with the pressure balance of the cyclone separator?
The gas mixture enters the cyclone tangentially and then separates through downward rotation. Solid feed leg, gas rises. When the wing valve gets stuck or the material leg is blocked, the cyclone operation is disrupted, and the gas mixture flows directly to the outlet. The gas mixture cannot be effectively separated, so the pressure drop decreases and the solid content increases. My personal understanding. The key performance indicators of a cyclone are pressure drop, differential pressure in the feed leg, and density of the feed leg; analyzing them together provides more accurate results.
In other words, whether the flap valve cannot be closed properly or cannot be opened properly, the result is the same – it leads to a decrease in pressure drop? So what causes the pressure drop to increase?
Coking blockage, large inlet harness, high catalyst density, external leakage, high steam volume