Calculation of oil-to-agent ratio
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It is known that the catalytic unit operates in a two-reactor, single-stage regeneration mode. The main operating conditions of this unit are shown in the table below:| Main Condition | Unit | Value |
|----------------|------|-------|
| Total wet main air flow | Nm3/h | 62500 |
| Total backflow air volume to the regenerator | Nm3/h | 500 |
| Mole ratio of water vapor to dry air | – | 0.02 |
| Reaction temperature | °C | 510 |
| Regenerator temperature | °C | 675 |
| Temperature at the outlet of the main fan | °C | 162 |
| Total steam volume entering the regenerator | Kg/h | 1000 |
| Steam temperature entering the regenerator | °C | 216 |
| Carbon dioxide content in the flue gas from regeneration | %V | 14.2 |
| Carbon monoxide content in the flue gas from regeneration | %V | 0.2 |
| Oxygen content in the flue gas from regeneration | %V | 4 |
| Heat loss of the regenerator | kJ/h | 2676836 |
| Total feed to the lift column | t/h | 155 |
What is the oil-to-catalyst ratio for this unit? (Keep two decimal places) Is there anyone who can do the calculation? It seems so difficult
The amount of charring is calculated based on the flue gas composition, and then the heat of combustion is determined; the circulation rate can be calculated using the heat required to raise the temperature of the catalyst. It’s best to check a reference book.